2x^2-2x-4512=0

Solution for 2x^2-2x-4512=0 equation:

2x^2-2x-4512=0

a = 2; b = -2; c = -4512;
Δ = b2-4ac
Δ = -22-4·2·(-4512)
Δ = 36100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36100}=190$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-190}{2*2}=\frac{-188}{4}
=-47
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+190}{2*2}=\frac{192}{4}
=48
$